Math, asked by ajharshal45, 1 month ago

if an isosceles triangle ABC, if AB = AC = 25 cm and BC = 14 cm. then find n find the measure of the altitude AD on BC​

Answers

Answered by Itsanshita
1

Step-by-step explanation:

In this triangle altitude from A to BC is AD, we know that isosceles altitude on non equal sides also median. Hence, the altitude AD on BC is 24 cm.

Answered by kabilasreesboa
0

Answer:

the altitude AD on BC  is 24 cm.

Step-by-step explanation:

Answer Expert Verified

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Vishank

Answer:

Step-by-step explanation:

Given :-

AB = AC = 25 cm and BC = 14 cm

To Find :-

In this triangle altitude from A to BC is AD, we know that isosceles altitude on non equal sides also median.

BD = CD = 14/2 = 7 cm

In ∆ADB,

By applying Pythagoras theorem, we get

AB² = AD² + BD²

⇒  25² = AD² + 7²

⇒  AD² = 625 − 49  

⇒  AD² = 576

⇒  AD = √576  

⇒  AD = 24 cm  

Hence, the altitude AD on BC  is 24 cm.

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