Question

If an isosceles triangle ABC, in which AB = AC = 6 cm, is inscribed in a
circle of radius 9 cm, find the area of the TRIANGLE.


GUYS PLEASE ANSWER TO THIS QUESTION. ​

Answer 1

Answer:

circumradius of isosceles ∆ = 9cm

9 = (6)²/2√[36*4-b²]

√(144-b²) = 2

144-b² = 4

b² = 140

b = 2√35 = base of isosceles ∆ .

now, Height = √(6)² -(√35)² = 1

so,

Area of isosceles ∆ = 1/2*base*Height = 1/2*2√35*1 = √35 cm² (Ans)

(Mark as brainlist if its correct)

Answer 2

Answer:

circumradius of isosceles ∆ = 9cm

9 = (6)²/2√[36*4-b²]

√(144-b²) = 2

144-b² = 4

b² = 140

b = 2√35 = base of isosceles ∆ .

now, Height = √(6)² -(√35)² = 1

so,

Area of isosceles ∆ = 1/2*base*Height = 1/2*2√35*1 = √35 cm² (Ans)

(Mark as brainlist if its correct)