if an isosceles triangle ABC, with AB = AC, the bisectors of B and ZC intersect each other at O. Join A to O . Show that: OB=OC AO bisects ZA
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∠C=∠B ∣ Since angles opposite to equal sides are equal
⇒21∠B=21∠C
⇒∠OBC=∠OCB
⇒∠ABO=∠ACO …(1)
⇒OB=OC ∣ Since sides opp. to equal ∠s are equal …(2)
(ii) Now, in △ABO and △ACO, we have
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