Question

IF AN ISOSCELES TRIANGLE HAS BASE b AND EQUAL SIDES a,THEN ITS AREA WII BE ANS WHAT​

Answer 1

Answer:

√3/4√a

a+b+c/2

1/2√4(a)2-(b)2

b√4(a)2_(b)2

Answer 2

$A= \frac{1}{2}\left [ \sqrt{\frac{a^2-b^2}{4}}\times b \right ]$

Step-by-step explanation:

the equal sides be  AB and AC = a

and third side BC of the isoceles triangle be b

therefore

area of isosceles triangle will be

$A= \frac{1}{2}\left [ \sqrt{\frac{a^2-b^2}{4}}\times b \right ]$

hence , area of isoceles triangle = $\frac{1}{2}\left [ \sqrt{\frac{a^2-b^2}{4}}\times b \right ]$

#Learn more:

If area of a square is 16 square meters,what wii be its parameter

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