if an isosceles triangle has perimeter 40cm. each of equal sides is 14cm. Find the area of the triangle .
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Perimeter of isosceles triangle=30cm
Length of equal sides=12cm
Let third side of triangle=xcm
According to problem,
x+12+12=30
x+24=30
x=30−24
x=6
∴ Third side of triangle=6cm
Using Heron's formula
Area of triangle= √s(s−a)(s−b)(s−c) sq. units
where s= a+b+c/2
s= 30/2 =15
Area of triangle= √15(15−12)(15−12)(15−6) cm²
= √15×3×3×9 cm²
=3×3× √15cm²
=9√15cm²
∴ Area of triangle=9√15 cm
.
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