if an isosceles triangle, length of the congruent sides is 13 cm and it's base is 10cm. Find the distance between the vertex opposite the base and the centroid
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heya it's Aastha !!!!!
Perimeter of the isosceles triangle = 13+13+10 = 36 cm = 2s
Area of triangle = [18(18–13)(18–13)(18–10)}^0.5 = [18*5*5*8]^0.5 = 60 sq cm.
Altitude of the triangle = 60*2/10 = 12 cm.
The centroid is 4 cm from the base and 8 cm from the vertex opposite the base
_________
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Perimeter of the isosceles triangle = 13+13+10 = 36 cm = 2s
Area of triangle = [18(18–13)(18–13)(18–10)}^0.5 = [18*5*5*8]^0.5 = 60 sq cm.
Altitude of the triangle = 60*2/10 = 12 cm.
The centroid is 4 cm from the base and 8 cm from the vertex opposite the base
_________
thnks @
hope it help you
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