if An=(n-1) (n-2), thn A1=
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An=(n-1) (n-2)
An=n²-3n+2
put n=1 in equation
1²-3(1)+2=1-3+2
=3-3=0
so first term of this is 0
A1=0
An=n²-3n+2
put n=1 in equation
1²-3(1)+2=1-3+2
=3-3=0
so first term of this is 0
A1=0
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