Question

if an =n/n+1 find a1+2a2​

Answer 1

Answer:

an=n/n+1, therefore a1= 1/1+1=1/2, a2=2/4=1/2 ,2a2=1, therefore on adding both 1/2+1,=3/2

Answer 2

Answer:

The value of the given expression is $a_1+2a_2=\frac{11}{6}$

Step-by-step explanation:

Given that the $a_n=\frac{n}{n+1}$

Now to find the value of $a_1+2a_2$

First to find $a_1$ and $a_2$

• Put n=1 in the given equation $a_n=\frac{n}{n+1}$ we have

$a_1=\frac{1}{1+1}$

$a_1=\frac{1}{2}$

• Put n=2 in the given equation $a_n=\frac{n}{n+1}$ we have

$a_2=\frac{2}{2+1}$

$a_2=\frac{2}{3}$

• Now find $a_1+2a_2$

Substitute the values in the above equation we get

$a_1+2a_2$

$=\frac{1}{2}+2(\frac{2}{3})$

$=\frac{1}{2}+\frac{4}{3}$

$=\frac{1(3)+4(2)}{6}$

$=\frac{3+8}{6}$

$=\frac{11}{6}$

Therefore $a_1+2a_2=\frac{11}{6}$