If an object fall from a height of 45 m what is the maximum velocity the object will fall with?
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Answer:
hey mate
Time taken to reach to the boat is t.
height (h)= 45m
h= ut+ 1/2at^2
45= 0+ 1/2 gt^2
t^2 = 45/10 x 2
= 3sec.
Given,
distance travelled by boat = 12m
Time taken will be (t) which is equal to 3 seconds
Velocity= 12/3 = m/s
=) 4m/sec.
Explanation:
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