if an object is 30 cm in front of a convex mirror that had a focal length of 60 cm, how far behind the mirror will be the image appear to an observer? how tall will the image be?
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The image is 20 cm behind the mirror, and the size of the image will be 2/3 times the size of the object.
Given,
The focal length = 60cm
Distance between the mirror and the object, v = 30cm
To find,
The image distance, v.
The magnification of the image, m.
Solution,
This question can be easily solved by the mirror formula.
the focal length, f = + 60 cm
u = - 30cm (since the object is on negative side)
Using mirror formula,
1/f = 1/u + 1/v
⇒ 1/60 = -1/30 + 1/v
⇒ 1/v = (1+2)/60
⇒ 1/v = 1/20
⇒ v = +20 cm
The magnification of the image,
m = -v/u
⇒ m = - (-20/30)
⇒ m = 2/3
Hence, we can conclude that the image is 20 cm behind the mirror, and the size of the image will be 2/3 times the size of the object.
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