Physics, asked by SavariShirke, 11 months ago

If an object is at rest reaches to a velocity
of 10 m/s and covers distance of 40 m
acceleration =?ā€‹

Answers

Answered by mandavimishra1115
1

Answer:

s=40 m

v=10 m/s

u=0 m/s

:- t=s/v

=40/10 s

=4 s.

:-a=v-u/t

=10-0/4 m/s^2

=10/4 m/ s^2

=0.25 m / s^2

acceleration of the object is 0.25 m /s^2.

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