Question

if an object is dropped from the top of a building and it reaches the ground at t = 4s then the height of the buliding ?

Answer 1

u=0
t= 4s
g = 9.8 or 10 m/s² I will take 10 (acceleration due to gravity)
using-
s=ut+1/2at²
s=0×4+1/2×10×4²
s=5×16
s=80 m
so height of the building is 80 m

Hope it helps:)
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