Question

If an object is dropped, how long will it take to attain a velocity of 127.4 m/sec?

Answer 1

v = g * t (v=velocity, t = time, g is gravity constant 9,82 m/s^2 on Earth)

Integrated for distance travelled:

h = 1/2 * g * t^2

Lets isolate t:

t^2 = 2h/g

t = sqrt (2h/g)

Lets insert your values:

t = sqrt (2 * 200m / 9,82 m/s^2) = 6,38 seconds

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