Question

If an object is placed at 10cm in front of a convex mirror of focal length 10cm. find the position of image and magnification​

Answer 1

Explanation:

Given; Focal length, f=20cm

Object distance, u=−10cm

Using mirror formula.

1/v+1/u=1/f

1/v=1/u-1/f

on putting value...

1/20 - (-10). ( u=-10)

1/20+1/10

30/20

v=20/3 cm...

Answer 2

Answer:

If an object is placed at $10cm$ in front of a convex mirror of focal length $10cm$ The position of the image $v=5cm$  and magnification​ is $0.5$

Explanation:

We have a mirror equation that relates object distance ($u$), image distance($v$), and focal length of the mirror ($f$) as

$1/v+1/u=1/f$

From the question, the focal length of the convex mirror is $f=10cm$

object distance $u=-10cm$ (negative sign is due to sign convention, distance against incident light is taken as negative)

substituting the values we get

$1/v=1/f-1/(-u)=1/f+1/u$

$1/v=1/10+1/10=1/5\\v=5cm$

The magnification is the ratio of the height of image to that of the object

$m=-(v/u)=-5/-10=0.5$