Question

if an object is placed at a distance of 10 cm from a concave mirror of focal length 15 centimetre the position of the image will be

Answer 1

Explanation:

The focal lenght is =15 cm

Object distance is 10 cm

So it is in between focal point and pole

So the image will be form beside the mirror

Its properties vertual erret and enlarge

Answer 2

Answer:-

U= -10 cm

f= 15 cm

1/f = 1/v + 1/u

So, 1/v= 1/f - 1/u

1/v= 1/15 + 1/10

1/v = (2+3)/30 (lcm)

Therefore v = 30/5 = 6 cm

Hence the image is formed behind the mirror and therefore it is virtual and erect.