if an object is placed at distance of 40cm from a convex lens of focal length 15cm. where and at what distance the image formed? will the image be virtual or real. .
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Heya
We can use the lens formulae here
Object distance = 40cm
Focal length = 15cm
1/f = 1/v - 1/u
Using sign convention
1/15 = 1/v - 1/(-40)
1/15 = 1/v + 1/40
1/15 - 1/40 = 1/v
(8-3)/120 = 1/v
5/120 = 1/v
1/24 = 1/v
v=24cm
The image will be formed at 24cm. The image will be a real one.
We can use the lens formulae here
Object distance = 40cm
Focal length = 15cm
1/f = 1/v - 1/u
Using sign convention
1/15 = 1/v - 1/(-40)
1/15 = 1/v + 1/40
1/15 - 1/40 = 1/v
(8-3)/120 = 1/v
5/120 = 1/v
1/24 = 1/v
v=24cm
The image will be formed at 24cm. The image will be a real one.
sravan6:
tnx dear
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