if an object is thrown at an angle of 60 degree with a initial velocity of 45m/ s.find the time of flight.also find the maximum height it will reach.
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Given u=40m/s, θ=60
0
and g=10m/s
2
Maximum Height H
Max
=
2g
u
2
sin
2
θ
=60m
Range R=
g
u
2
sin2θ
=80
2
3
m
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