Question

if an object is thrown vertically upward with a speed 49 MS -1 how long does it take to complete upward in journey what maximum height does it achieve

Answer 1

t=u/g
=49/9.8
=5s

h=u²/2g
=49*49/2*9.8
=112.5 m

Answer 2

(i) v=u+at
0=49-9.8t
t=5
(ii)v^2=u^2 +2as
0= 49*49-2*9.8s
s=49*49/19.6
s=245/2
s=122.5