If an object is thrown vertically upwards with a speed of 49m/s.How long does it take to complete the upwards journey?What is the maximum height achieved?
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U=49M/S
g=9.8m/s^2
hmax=U^2/2g
hmax=49^2/19.6
hmax=122.5m
U=49M/S
g=9.8m/s^2
hmax=U^2/2g
hmax=49^2/19.6
hmax=122.5m
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