Question

If an object is thrown vertically upwards with speed of 49 m/s. How long does it take to complete upward journey? What maximum heightndoes it achieve? (Full explanation )

The person who will answer correctly and fastly will get brainliest tag.... ​

Answer 1

u= 49

g= 9.8

time of ascend = u/g=49/9.8

=5 s

now maximum height,

s=ut+1/2at2

=49*5+1/2*9.8*5*5

=367.5

that much....