Question

If an object is traveling with a velocity of 10m/s and the acceleration is -5m/s^2.fimd the distance covered after 4 seconds

Answer 1

Answer:

u= 10m/s

acc= (-5m/s square)

t= 4 sec

s = ut +1/2 at square

s= 10×4+1/2×(-5)(4)square

s= 40+1/2(-5)(16)

s= 40-40

s= 0

Answer 2

Given:-

u(initial velocity)=10m/s

a= -5m/s²

t=4 seconds

To find:-

s(distance)

Solution:-

By using s=ut+1/2at² we get-----

s=10×4+1/2(-5)(4)²

s=40+(-40)

s=0

Thus,distance covered in 4 seconds is 0m.