Question

If an object move 3 km in East and turn right and moves up to 4 km what is the displacement​

Answer 1

Answer:

5 km towards south-east

Explanation:

As per the provided information in the given question, we have :

• An object moves 3 km in East and turn right and moves up to 4 km.

We've been asked to calculate the displacement.

Displacement is the shortest distance from the initial position to the final position. It is a vector quantity. Its SI unit is metre (m). Here, the initial position is A and the final position is B. The shortest distance between two points is always a straight line. So, AC is the shortest distance from point A to point B.

We can easily calculate the length of AC using the Pythagoras property.

Here,

• AB = Base
• BC = Perpendicular
• AC = Hypotenuse/Displacement

$\longrightarrow \sf{\quad {H^2 = B^2 + P^2 }}$

$\longrightarrow \sf{\quad {(AC)^2 = (AB)^2 + (BC)^2 }}$

$\longrightarrow \sf{\quad {(AC)^2 = (3 \;km)^2 + (4 \; km)^2 }}$

$\longrightarrow \sf{\quad {(AC)^2 = 9 \;km^2 + 16 \; km^2 }}$

$\longrightarrow \sf{\quad {(AC)^2 = 25 \; km^2 }}$

$\longrightarrow \sf{\quad {AC= \sqrt{25 \; km^2} }}$

$\longrightarrow \quad\sf { AC= 5 \; km }$

So,

$\longrightarrow \quad\underline{\boxed { \pmb{\frak{ Displacement}} = \pmb{\frak{5 \; km}}_{( \pmb{\frak{towards \; south-east)}}} } }$

Therefore, the displacement is 5 km towards south-east.