if an object moving with velocity Vm/s comes to rest after applying brakes in T seconds. State the distance covered by it after applying brakes
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Answer:
s= Vt+t^2
Explanation:
u = Vm/s
v = 0m/s
t = t sec
v=u+at
a=v-u/t
a=V -0/t
s= ut+1/2at^2
s= Vt +1/2×V -0/t×t^2
s= Vt+1/2×t(V-0)×t^2
s= Vt+1/2×Vt×t^2
s= 2Vt+1/2+t^2
s= Vt+t^2
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