Question

if an object of 10 cm height is placed at a distance of 36 cm from a concave mirtor of focal lenght 12cm find height position nature of image ​

Answer 1

1/v + 1/u = 1/f

u = -36cm f = -12 cm

1/v = -1/12 + 1/36 = -1/18 so v= -18 cm

m = - v/u = -1/2

height of the image = 10 cm * -1/2 = -5 cm

so image is real inverted and of height 5 cm.

Answer 2

Answer:

Explanation:

Height 2.5cm

Image is of same size formed at the object

Inverted