Question

if an object of 10 cm height is placed at a distance of 36 cm from a concave mirror of focal length 12 cm find the nature position and height of image​

Answer 1

here is your answer it might help you

Answer 2

ho=10cm

u=-36cm

v=?

f=-12cm

by mirror formula

$\frac{1}{v} + \frac{1}{u } = \frac{1}{f}$

$\frac{1}{v} = \frac{- 1}{12} - ( \frac{ - 1}{36} )$

$\frac{1}{v } = \frac{1}{36} - \frac{1}{12}$

$\frac{1}{v} = \frac{1 - 3}{36}$

$\frac{1}{v} = \frac{ - 2}{36}$

$v = - 18$

--->so image is" -18cm" from the mirror and is "real and inverted".

$m = \frac{hi}{ho} = \frac{ - v}{u}$

$\frac{10}{hi} = - ( \frac{ -18}{ - 36} )$

$hi = - \frac{1}{2} \times \frac{1}{10}$

$hi= - 0.05cm$

--->hence the height of the image is -0.05cm