if an object of 10 cm in height is placed at a distance of 36 cm from a concave mirror of focal length 12 centimetre find the position nature and height of the image
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1/f = 1/v + 1/u
1/12 = 1/v +1/36
1/v = 1/12 - 1/36
1/v = 3-1/36
1/v = 2/36
1/v = 1/18
therefore v = 18cm
h'/h = -v/u
h'/10 = -18/36
h'/10 = -1/2
h'= -1/2(10)
h'= -5cm
((not sure for the answer ))
1/12 = 1/v +1/36
1/v = 1/12 - 1/36
1/v = 3-1/36
1/v = 2/36
1/v = 1/18
therefore v = 18cm
h'/h = -v/u
h'/10 = -18/36
h'/10 = -1/2
h'= -1/2(10)
h'= -5cm
((not sure for the answer ))
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Answer:
hi
change ur question i will answer
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