if an object of 10cm is placed at a distance of 36 centimetres from a concave mirror of focal length 12 centimetre find the position, nature and height of the mirror
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GIVEN :
ho=10cm
u=-36cm
f= -12cm
hi=?
SOLUTION:
1/f = 1/v + 1/u
1/-12 = 1/v + 1/-36
1/36 + 1/-12 = 1/v
(Lcm 36&12=36)
1-3/36 = 1/v
1/v= -18
v= -18
m=hi/ho = -v/u
= hi= -v.ho/u
= -(-18) 10/ 36
= 180/36
hi = 5cm
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HOPE IT HELPS
MARK BRAINLIEST
vvkkharat25:
nature virtual and erect
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