Question

if an object of 2kg moving with a velocity 6m/s, it strikes on object reduces 3m/s find kinetic energy.

Answer 1

Answer:

If an object of mass $2Kg$ moving with a velocity $6m/s$, it strikes on an object and reduces velocity to $3m/s$, the kinetic energy after collision is $9J$

Explanation:

The kinetic energy for any moving object can be calculated as long as the mass and speed of the object are known.

Here mass of the moving body is $m=2Kg$

Initial kinetic energy of the object is $KE_{1}$$=\frac{1}{2}mV_{1} ^{2}$

It can be calculated as $KE_{1}=\frac{1}{2}.2.36=36J$

Now, the object strikes on another object and velocity is reduced to $V_{2}$

The value is given as $V_{2} =3m/s$

Then, the kinetic energy of the body $KE_{2}=\frac{1}{2}mV_{2} ^{2}$

After substituting the values, the kinetic energy of the body is $KE_{2}=\frac{1}{2}.2.9=9J$

The change in kinetic energy is $36-9=27J$