Question

if an object of 7 cm is placed at a distance of 12 cm from a convex lens of focal length 8 cm find the position size height and nature of image​

Answer 1

Answer:

the nature if image is real, inverted ,magnified

Answer 2

➭ Question :-

$⟶$if an object of 7 cm is placed at a distance of 12 cm from a convex lens of focal length 8 cm find the position size height and nature of image

➭ Given :-

$⟶$Object distance,u = 12cm

$⟶$Focal length,f = 8cm

$⟶$Object height, h = 7cm

➭ To find :-

$⟶$The position , image distance and nature of image

➭ Formula required :-

$⟶$$\boxed{\sf \frac{1}{f} = \frac{1}{v} - \frac{1}{u} }$

➭ Solution :-

using lens formula,

$\tt ⟹ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \: \: \: \\ \\ \tt ⟹ \frac{1}{8} = \frac{1}{v} - \frac{1}{12} \: \\ \\ \tt ⟹ \frac{1}{v} = \frac{3 - 2}{24} \: \: \: \: \\ \\ \tt ⟹ \frac{1}{v } = \frac{1}{24} \: \: \: \: \: \: \: \: \:$

$\boxed{\sf V = 24cm}$

$\tt ⟹ m = \frac{h'}{h} = \frac{v}{u} \\ \\ \tt ⟹ \frac{ - 24}{12} = \frac{h'}{7} \: \: \: \: \\ \\ \tt ⟹ h' = - 2 \times 7$

$\boxed{\sf h' = -14cm}$

Hence, image height = -14cm and image distance = 24cm

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➭ Nature of the image....

• Image is real and inverted
• Image is formed beyond 2F
• Image is enlarged