If an object of 7m height is placed at a distance of 12cm from a convex lens of focal length 8cm ...find the position ,nature and height
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The object is placed between 2f and f so the image thus formed will be beyond 2f.
Image formed will be real and inverted.
Image formed will be real and inverted.
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Answer:
Given f=-8 cm
U=12cm
Height of object = 7m
Now,
W.k.t 1/f+1/u = 1/v
1/-8+1/12 = 1/v
-3+2/24 = 1/v
-1/24= 1/v
V =-24 cm
W.k.t hi/ho= -v/u
Hi/7= -(-24)/-12
Hi/7 = -2cm
Hi= 14 cm
The object is between center of curvature and focus so image is obtained beyond center of curvature
Real inverted magnified
Explanation:
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