If an object of height 10 cm from a concave mirror of focal length 12cm, find the position,nature and height of the image .
subhambanerjee1703:
Where is it placed???
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POSITION:
1/F=1/V-1/U
1/12=1/V-1/-36
1/12-1/36=1/V
3-1/36=1/V
2/36=1/V
AFTER CANCELLATION
1/18=1/V
V=18
MAGNIFICATION;
M=-V/U
M=-18/-36
AFTER CANCELLATION
M=1/2
M=-2
HEIGHT OF IMAGE=-2xHEIGHT OF OBJECT
AS (-) SIGN IS THERE, IGNORE IT (-) SIGN JUST STATES THAT IMAGE IS INVERTED I.E BELOW THE AXIS....
NATURE:
----DIMNISHED
----BETWEEN F AND C
----REAL
----INVERTED
BRAINLY PLZZZZZ.....
HOPE THIS HELPS U... :)
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