If an object of height 4 cm is placed at distance of 12 cm from a concave mirror having focal length 24 cm, find the position, nature and the height of the image.
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h = 4 cm
u = -12 cm
f = -24 cm
1/v = 1/f - 1/u
1/v = -1/24 + 1/12
1/v = -1+2/24
v = 24cm
height of image = -v/u *h = 2*4 = 8cm
the image formed is real, erect and enlarged and formed at centre of curvature
u = -12 cm
f = -24 cm
1/v = 1/f - 1/u
1/v = -1/24 + 1/12
1/v = -1+2/24
v = 24cm
height of image = -v/u *h = 2*4 = 8cm
the image formed is real, erect and enlarged and formed at centre of curvature
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