If an object of mass 30kg is placed on a plane which makes an angle of 300 with the
horizontal then the PE of the object is 3000J. Find the length of inclined plane if g=10m/s2
.
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Explanation:
mgsin37
0
=10×10×3/5=60N
f
l
=μ=0.2mgcos37
0
=0.2×10×10×4/5
=16N
Friction force alone is unable to balance mgsin37
0
. Hence, F is required for balancing. Here two cases arise.
Case I:
If the block has tendency to slide down, friction on block will act upwards.
F + 16 = 60
RightarrowF=44N
This is the minimum force required for balancing.
Case II: If the block has on tendency to slide up, friction on block will act downwards.
F = 60 + 16⇒ F= 76 N
This is the maximum force required for balancing.
Therefore, for balancing 44N≤F≤16N
solution
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