if an object reaches a maximum heigh of 23m on the earth, how high will it trave on the moon where acceleration due to gravity about one sixth than on the moon
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h=(2u)/g
23 = (2u)/g
23(g)= 2u-----------------(1)
h-moon =(2u)/(g/6)
h-moon =23g/(g/6)
=138m
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23 = (2u)/g
23(g)= 2u-----------------(1)
h-moon =(2u)/(g/6)
h-moon =23g/(g/6)
=138m
GLAD YOU LIKE IT
PLEASE MAKE ANSWER AS BRAINLIEST
Answered by
1
maximun height(h) reached by an object of initial velocity (u) is,
h=u^2/2g, where g= acceleration due to gravity
since g becomes 1/6 on moon so,
h=u^2/(2g/6)
h=6*u^2/2g
Therefore , maximum height will be 6 times more on moon.
therefore, h=6*23= 138m
h=u^2/2g, where g= acceleration due to gravity
since g becomes 1/6 on moon so,
h=u^2/(2g/6)
h=6*u^2/2g
Therefore , maximum height will be 6 times more on moon.
therefore, h=6*23= 138m
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