If an object subtend angle of 2° at eye when seen through telescope having objective and
eyepiece of focal length f. = 60 cm and f. = 5 cm respectively than angle subtend by
image at eye piece will be
a) 16°
b) 50°
c) 24°
d) 10°
fon
netronomical telescone for normal
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Answer:
M=
α
β
=
f
e
f
0
∴β=
f
e
f
0
α=
5
60
×2
o
=24
o
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