If an object throw with velocity v & at an angle q with ground.Then find.
(a) Horizontal Range
(b) equation of trajectory of object
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Answer:
a)range =u^²sin2A/g
Explanation:
where u is initial velocity and A is angle of projection and g is acceleration due to gravity
put the respective values and get the answer
b) as it move in a plane we have to write the equations in two directions x and y
for
x =vcosp .t
and for y=usinp.t -1/2gt^²
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