Question

If an object weighing 40kg is 0.5.m away from an object weighing 60kg, what is its gravitational pull?

Answer 1

Answer:

$\sf 640.32 \times 10^{-9}$ N

Explanation:

As per the provided information in the given question, we have :

• Mass of first object, m = 40 kg
• Mass of another object, M = 60 kg
• Distance between them, d = 0.5 m

We've been asked to calculate its gravitational pull i.e, gravitational force, F.

As we know tha gravitational force is given by,

⠀⠀⠀⠀⠀⠀⠀$\underline{\boxed{ \textbf{\textsf{F = }} \textbf{\textsf{G}}\dfrac{\textbf{\textsf{Mm}}}{\textbf{\textsf{d}}^{\textbf{\textsf{2}}}} }}$

Value of G is $\sf 6.67 \times 10^{-11}$

On substituting values,

$\\ \\ \longrightarrow\sf{F = \dfrac{6.67 \times 10^{-11}\times 40 \times 60}{(0.5)^2} \; N }$

$\\ \\ \longrightarrow\sf{F = \dfrac{6.67 \times 10^{-11}\times 2400}{0.25} \; N }$

$\\ \\ \longrightarrow\sf{F = \dfrac{667 \times 10^{-11}\times 2400 \times 100 }{25 \times 100} \; N }$

$\\ \\ \longrightarrow\sf{F = \dfrac{667 \times 10^{-11}\times 24 \times 100 \times 100 }{25 \times 100} \; N }$

$\\ \\ \longrightarrow\sf{F = \dfrac{667 \times 10^{-11}\times 24 \times 10^4 }{25 \times 10^2} \; N }$

$\\ \\ \longrightarrow\sf{F = \dfrac{667 \times 10^{-7}\times 24 }{25 \times 10^2} \; N }$

$\\ \\ \longrightarrow\sf{F = \dfrac{667 \times 10^{-7 - 2}\times 24 }{25} \; N }$

$\\ \\ \longrightarrow\sf{F = \dfrac{667 \times 10^{-9}\times 24 }{25} \; N }$

$\\ \\ \longrightarrow\sf{F = \dfrac{667 \times 10^{-9}\times 24 }{25} \; N }$

$\\ \\ \longrightarrow\sf{F = \dfrac{16008 \times 10^{-9}}{25} \; N }$

$\\ \\ \longrightarrow \underline{\underline{\textbf{\textsf{F = 640.32}} \times \textbf{\textsf{10}}^{\textbf{\textsf{-9}}}\; \textbf{\textsf{N}} }}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Therefore, its gravitational pull is $\sf 640.32 \times 10^{-9}$ N.

⠀⠀⠀_____________________________⠀⠀⠀

Answer 2

Answer:

Given :-

• An object weighing 40Kg is 0.5.m away from an object weighing 60 kg.

To Find :-

• What is it's gravitational pull.

Formula Used :-

$\clubsuit$ Gravitational Force Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{F =\: \dfrac{GMm}{r^2}}}}\: \: \: \bigstar$

where,

• F = Gravitational Force
• G = Gravitational Constant
• M = Mass of one object
• m = Mass of other object
• r = Distance between the two object

Solution :-

Given :

❒ Mass of one object (M) = 40 kg

❒ Mass of other object (m) = 60 kg

❒ Distance between the two object (r) = 0.5 m

❒ Gravitational Constant (G) = $\bf 6.67 \times 10^{- 11}$

According to the question by using the formula we get,

$\implies \sf\bold{\purple{F =\: \dfrac{GMm}{r^2}}}$

$\implies \sf F =\: \dfrac{6.67 \times 10^{- 11} \times 40 \times 60}{(0.5)^2}$

$\implies \sf F =\: \dfrac{6.67 \times 10^{- 11} \times 2400}{0.5 \times 0.5}$

$\implies \sf F =\: \dfrac{6.67 \times 10^{- 11} \times (24 \times 100)}{0.25}$

$\implies \sf F =\: \dfrac{(667 \times 100) \times 10^{- 11} \times (24 \times 100)}{(25 \times 100)}$

$\implies \sf F =\: \dfrac{667 \times 10^2 \times 10^{- 11} \times 24 \times 10^2}{25 \times 10^2}$

$\implies \sf F =\: \dfrac{667 \times 10^{- 11} \times 24 \times 10^2 \times 10^2}{25 \times 10^2}$

$\implies \sf F =\: \dfrac{667 \times 10^{- 11} \times 24 \times 10^{(2 + 2)}}{25 \times 10^2}$

$\implies \sf F =\: \dfrac{667 \times 10^{- 11} \times 24 \times 10^4}{25 \times 10^2}$

$\implies \sf F =\: \dfrac{667 \times 10^{- 11} \times 10^4 \times 24}{25 \times 10^2}$

$\implies \sf F =\: \dfrac{667 \times 10^{(- 11 + 4)} \times 24}{25 \times 10^2}$

$\implies \sf F =\: \dfrac{667 \times 10^{- 7} \times 24}{25 \times 10^2}$

$\implies \sf F =\: \dfrac{667 \times 10^{(- 7 - 2)} \times 24}{25}$

$\implies \sf F =\: \dfrac{667 \times 24 \times 10^{- 9}}{25}$

$\implies \sf F =\: \dfrac{16008 \times 10^{- 9}}{25}$

$\implies \sf\bold{\red{F =\: 640.32 \times 10^{- 9}\: N}}$

$\sf\bold{\underline{\therefore\: The\: gravitational\: pull\: is\: 640.32 \times 10^{- 9}\: N\: .}}$