Question

If an object weighs 400 N on the surface of the earth,what is the weight of the same object in the surface of a heavenly body having mass two times and radius half of the moon.​

Answer 1

Answer:

We know that in Newtonian mechanics, F = Gm1m2/r^2

Where F is the attractive force between 2 masses, m1 and m2, r is the distance between the centres of the masses and G is the universal gravitation constant, which is 6.674x10^-11 Nm^2/kg^2

IF, however, one mass is much greater than the other, we can write

g = GM/r^2 where M is the larger mass

the mass of the earth is m(e) and the radius of the earth is r(e)

the mass of Planet X is 4m(e) and the radius is 2r(e)

so g(earth) = Gm(e)/r(e)^2

and g(X) = 4Gm(e)/2r(e)^2

so the ratio is [4Gm(e)/2r(e)^2] / [Gm(e)/r(e)^2] = 1

The body which weighs 100N on earth weighs 100N on Planet X.

Explanation:

this is the method of doing