Physics, asked by hansraj14122003, 21 days ago

If an object with a force of m is moved to a height of nR, its position changes with the change in energy.​

Answers

Answered by neerujaiverma
0

Answer:

Correct option is

A

(

n+1

n

)mgR

Gravitational potential energy of mass m at any point at a distance r from the centre of earth is

U=−

r

GMm

At the surface of earth r=R,

∴U

s

=−

R

GMm

=−mgR(∵g=

R

2

GM

)

At the height h=nR from the surface of earth

r=R+h=R+nR=R(1+n)

∴U

h

=−

R(1+n)

GMm

=−

(1+n)

mgR

Change in gravitational potential energy is

△U=U

h

−U

s

=−

(1+n)

mgR

−(−mgR)

=−

1+n

mgR

+mgR

=mgR(1−

1−n

1

)=mgR(

1+n

n

).

Answered by diyalis
1

Answer:

i hope that this attachment can help u my dear friend

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