If an object with a force of m is moved to a height of nR, its position changes with the change in energy.
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Answered by
0
Answer:
Correct option is
A
(
n+1
n
)mgR
Gravitational potential energy of mass m at any point at a distance r from the centre of earth is
U=−
r
GMm
At the surface of earth r=R,
∴U
s
=−
R
GMm
=−mgR(∵g=
R
2
GM
)
At the height h=nR from the surface of earth
r=R+h=R+nR=R(1+n)
∴U
h
=−
R(1+n)
GMm
=−
(1+n)
mgR
Change in gravitational potential energy is
△U=U
h
−U
s
=−
(1+n)
mgR
−(−mgR)
=−
1+n
mgR
+mgR
=mgR(1−
1−n
1
)=mgR(
1+n
n
).
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1
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