Math, asked by suryakalakommireddy, 8 months ago

If an ordered pair satisfying the equations 2x-3y=18 and 4x-y=16
also satisfies the equation 5x-py-23=0, then find the value of p?​

Answers

Answered by abhi178
32

It has given that, an ordered pair (x, y) satisfying 2x - 3y = 18 and 4x - y = 16 also satisfies the equation 5x - py - 23 = 0.

We have to find the value of p.

solution : first solve the equation 2x - 3y = 18 and 4x - y = 16

Let 2x - 3y = 18.....(1)

4x - y = 16 ....(2)

multiplying 3 with equation (3) and then subtracting from equation (1)

i.e., 2x - 3y - 3(4x - y) = 18 - 3 × 16

⇒2x - 3y - 12x + 3y = 18 - 48 = -30

⇒-10x = -30

⇒x = 3

Now putting x = 3 in equation (2) we get,

4(3) - y = 16 ⇒y = -4

Therefore ordered pair is (3, -4), it also satisfies equation 5x - py - 23 = 0

So, 5(3) - p(-4) - 23 = 0

⇒15 + 4p - 23 = 0

⇒4p - 8 = 0

⇒p = 2

therefore the value of p is 2.

Answered by gskswapna
22

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