Question

If an ore contains 18% of iron. How many tons of ore will produce 30 tons of iron?

Answer 1

Given that an ore contains 18% of iron.

Now, suppose, x tons of ore is required to produce 30 tons.

So, according to the question

18% of x=30 tons

x= 30/18%

x= 30*100/18=166.66

Therefore, 166.66 tons are required to produce 30 tons of iron.