Question

If an Triangle ABC right angled at B, AB = 6 units and BC = 8 units then find the value of sin A.cos A + cos A.sin C.

Answer 1

Answer:

Answer is 0.83994

Step-by-step explanation:

In triangle ABC, For angle A

adj = AB = 6

opp = BC = 8

tan A = opp/adj = 8 / 6

A = atan(8/6) = 53.13 deg

B = 90 deg

C = 180 - (90+53.13) = 36.87 deg

sinA.cosA+cosA.sinC = sin53.13.cos53.13+cos53.13.sin36.87 = 0.7999*0.6+0.6*0.6 = 0.47994+0.36=0.83994