Question

if an unbiased coin is tossed twice find the probability of obtaining at least one head​

Answer 1

Answer:

P(E)=3/4

Step-by-step explanation:

When unbiased coin is tossed twice,the all possible outcomes are:

(H, H), (H, T), (T, H) and (T, T).

Total number of possible outcomes = 4

Let E be the getting at least one tail.

The favorable outcomes are:

(H, T), (T, H) and (T, T).

Number of favorable outcomes = 3

∴ Probability, P(E) =$\frac{Number\ of\ favorable\ outcomes}{ total\ number\ of\ possible\ outcomes}$

P(E) =$\frac{3}{4}$

Answer 2

Answer:

Answer:

P(E)=3/4

Step-by-step explanation:

When unbiased coin is tossed twice,the all possible outcomes are:

(H, H), (H, T), (T, H) and (T, T).

Total number of possible outcomes = 4

Let E be the getting at least one tail.

The favorable outcomes are:

(H, T), (T, H) and (T, T).

Number of favorable outcomes = 3

∴ Probability, P(E) =\frac{Number\ of\ favorable\ outcomes}{ total\ number\ of\ possible\ outcomes}

total number of possible outcomes

Number of favorable outcomes

P(E) =\frac{3}{4}

4

3

Step-by-step explanation:

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