Question

If an unbiased die is rolled once, the odds in favour of getting a point which is a multiple of 3 is ​

Answer 1

Given :

Number of total outcomes = 6

Number of outcomes multiple of 3 = 2 i.e. {3,6}

Number of outcomes not multiple of 3 = $6-2=4$

To find : odds in favor of getting a point which is a multiple of  is ?

Solution :

Probability of getting a multiple of 3 would be :

$\dfrac{2}{6}=\dfrac{1}{3}$

Probability of getting not multiple of 3 would be :

$\dfrac{4}{6}=\dfrac{2}{3}$

Hence, the odds in favor of getting a point is $\dfrac{1}{3}:\dfrac{2}{3}=1:2$