Question

if an wire with 8ohm resistance is melted and a new wire made with double the cross section what would be the resistance of the new wire​

Answer 1

Explanation:

Hey mate ,

This is your answer ,

Given Resistance of a wire

Given Resistance of a wireR=

Given Resistance of a wireR= A

Given Resistance of a wireR= ApL

Given Resistance of a wireR= ApL

Given Resistance of a wireR= ApL

Given Resistance of a wireR= ApL On, stretching a wire (a) volume of wire remains constant

Given Resistance of a wireR= ApL On, stretching a wire (a) volume of wire remains constant(b) length of wire increases

Given Resistance of a wireR= ApL On, stretching a wire (a) volume of wire remains constant(b) length of wire increases(c) Area of cross section decreases

Given Resistance of a wireR= ApL On, stretching a wire (a) volume of wire remains constant(b) length of wire increases(c) Area of cross section decreases(d) Resistivity of wire = constant

Given Resistance of a wireR= ApL On, stretching a wire (a) volume of wire remains constant(b) length of wire increases(c) Area of cross section decreases(d) Resistivity of wire = constantOn doubling length by stretching :

Given Resistance of a wireR= ApL On, stretching a wire (a) volume of wire remains constant(b) length of wire increases(c) Area of cross section decreases(d) Resistivity of wire = constantOn doubling length by stretching :L 1 =2L

=2LA1 =A/2

=2LA1 =A/2∴R1= A1pL1 = 2AAp(2L) = A4pL = 4R

Answer 2

Answer:

can HB NC u BC CCC can CX z. hb