If α and 1/α are zeroes of 4x² -17x + k - 4, find value of k.
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Let p(x) = 4x² -17x + k - 4
On comparing with ax² + bx + c
a= 4, b= -17 , c= k- 4
Given, α and 1/α are the zeroes of p(x).
Product of zeroes(α.1/α)= c/a
α.1/α = (k-4)/4
1 ×4 = k-4
4+4 = k
k = 8
Hence, the value of k is 8.
HOPE THIS WILL HELP YOU...
Let p(x) = 4x² -17x + k - 4
On comparing with ax² + bx + c
a= 4, b= -17 , c= k- 4
Given, α and 1/α are the zeroes of p(x).
Product of zeroes(α.1/α)= c/a
α.1/α = (k-4)/4
1 ×4 = k-4
4+4 = k
k = 8
Hence, the value of k is 8.
HOPE THIS WILL HELP YOU...
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