If α and β ae the zeroes of the quadratic polynomial f (x) = x2 + x – 2, then find a polynomial whose zeroes are 2α + 1 and 2β + 1.
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α and β ae the zeroes of the quadratic polynomial f (x) = x² + x – 2.
so, sum of zeroes = - coefficient of x/coefficient of x²
or, (α + β) = -1/1 = -1 ......(1)
and product of zeroes = constant/coefficient of x²
or, αβ = -2/1 = -2 .......(2)
now we have to find polynomial whose zeroes are 2α + 1 and 2β + 1
we know, any quadratic polynomial is in the form of, x² - (sum of zeroes)x + product of zeroes.
= x² - (2α + 1 + 2β + 1)x + (2α +1)(2β + 1)
= x² - {2(α + β) + 2}x + {4αβ + 2(α + β) + 1}
from equations (1) and (2),
= x² - {2(-1) + 2}x + {4(-2) + 2(-1) + 1}
= x² - 0.x + {-9}
= x² - 9
hence, required polynomial is x² - 9
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