if α and β are acute angles satisfying sinα = 1/2, cosβ = 1/3 , then α+β∈ to
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sin(α+β) = sinαcosβ + cosαsinβ
= (1/2×1/3) + (√3/2 × 2√2/3)
= 1/6 + √(2/3)
so (α+β) = sin⁻¹ (1/6 + √(2/3))
= (1/2×1/3) + (√3/2 × 2√2/3)
= 1/6 + √(2/3)
so (α+β) = sin⁻¹ (1/6 + √(2/3))
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