If α and β are roots of 6 x2-7x-3=0 , find the value of α2+β2
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Answered by
3
hey friend !!!
@ + bita=- cofficient of x/cofficient of x²
@+bita= - (- 7/6)
@+bita=+7/6-----1)
and @×bita =constant term /cofficient of x²
@×bita =-3/6=-1/2 ------2)
now...by using ( a+b)²=a²+b²+2ab formula
just like this ...
(@+bita)²-2@×bita =@²+bita²
(7/6)²-2(-1/2). .. [by using 1 and 2]
=>49/36+1
=>49+36/36
=>85/36 Answer
hope it helps you !!!
@rajukumar111
@ + bita=- cofficient of x/cofficient of x²
@+bita= - (- 7/6)
@+bita=+7/6-----1)
and @×bita =constant term /cofficient of x²
@×bita =-3/6=-1/2 ------2)
now...by using ( a+b)²=a²+b²+2ab formula
just like this ...
(@+bita)²-2@×bita =@²+bita²
(7/6)²-2(-1/2). .. [by using 1 and 2]
=>49/36+1
=>49+36/36
=>85/36 Answer
hope it helps you !!!
@rajukumar111
rinki786:
thanks..
Answered by
1
the answer is 85/36
HOPE IT HELPS
HOPE IT HELPS
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