Math, asked by ys1397266, 9 months ago

If α and β are roots of quadratic equation 2 x2

- 10 x + 5 = 0 the value of 1

+

1

is​

Answers

Answered by Anonymous
4

Answer: The answer is given in the attachment

Attachments:
Answered by mysticd
0

 Given \:\alpha \: and \: \beta \:are \: roots \:of

 a \: Quadratic \: equation \: 2x^{2}-10x+5=0

 i) Sum \:of \: the \:roots = \frac{Coefficient \:of \: x }{Coefficient \:of \: x^{2}}

 \implies \alpha + \beta = \frac{-(-10)}{2}

 = \frac{10}{2}

 = 5 \: --(1)

 ii) Product\:of \: the \:roots = \frac{Constant \:term}{Coefficient \:of \: x^{2}}

 \implies \alpha \beta = \frac{5}{2}

 = \frac{5}{2}\: ---(2)

 \red{ Value \: of \: \frac{1}{\alpha} + \frac{1}{\beta}}

 = \frac{\beta + \alpha }{\alpha \beta }

 = \frac{ 5}{\frac{5}{2}}

 = 5 \times \frac{2}{5}

 = 2

Therefore.,

 \red{ Value \: of \: \frac{1}{\alpha} + \frac{1}{\beta}} \green { = 2 }

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